20a^2-20a+5=0

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Solution for 20a^2-20a+5=0 equation: 



20a^2-20a+5=0

a = 20; b = -20; c = +5;
Δ = b2-4ac
Δ = -202-4·20·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{20}{40}=1/2$

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